Surface Area Word Problems 7th Grade

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7th Grade Algebra Word Problems
Surface Area Word Problems 6th Grade
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7th Grade Math Word Problems Worksheets

Surface Area of a Solid Cylinder

A cylinder is a solid that has two parallel faces which are congruent circles. These faces form the bases of the cylinder. The cylinder has one curved surface. The height of the cylinder is the perpendicular distance between the two bases.

The net of a solid cylinder consists of 2 circles and one rectangle. The curved surface opens up to form a rectangle.

Surface area = 2 × area of circle + area of rectangle
Surface Area = 2πr²

+ 2πrh = 2πr(r + h)
$Word$ where r is the radius and h is the height.
Worksheets
Calculate the volume of cylinders
Calculate the surface area of cylinders
Volume and surface area of cylinders
Surface area of cylinders and pipes

Example:

The diameter of the base of a cylinder is 12 cm and the height is 8 cm. Find the surface area of the solid cylinder.

Solution:

Radius = 6 cm
Surface area = 2πr (r + h)
=
= 528 cm²How to derive and use the formula of the surface area of a cylinder?

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How to find the surface area of a cylinder? Example:
Find the surface area of a cylinder with r = 18in, h = 17in. How to calculate the surface area of a cylinder in terms of pi?

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Surface area of a hollow cylinder

Sometimes you may be required to calculate the total surface area of a hollow cylinder or tube or pipe.

Total surface area of hollow cylinder
= area of internal curved surface + area of external curved surface + area of the two rings

Example:

The figure shows a section of a metal pipe. Given the internal radius of the pipe is 2 cm, the external radius is 2.4 cm and the length of the pipe is 10 cm. Find the total surface area of the pipe

Solution:

r = 2, R = 2.4, h = 10

Total surface area of pipe
= area of internal surface + area of external surface + area of the two rings
= 2πrh + 2πRh + 2(πR²– πr²)
= (2π × 2 × 10) + (2π × 2.4 × 10) + (2 × (2.4²π – 2

7th Grade Word Problem Practice

²π))
= 40π + 48π + 3.52π
= 91.52π
= 91.52 × 3.142
= 287.56 cm²

Word problems about cylinders

Problem:
How many square feet of metal are used to make the can?

Show Step-by-step Solutions

Problem:
Find the surface area of a cylinder without the lid.

Surface Area of cylinder using nets

Use the net of a cylinder to determine its volume and surface area.

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Problem 1 :

Erin is making a jewelry box of wood in the shape of a rectangular prism. The jewelry box will have the dimensions shown below. The cost of painting the exterior of the box is $0.50 per square in. How much does Erin have to spend to paint the jewelry box ?

Problem 2 :

A metal box that is in the shape of rectangular prism has the following dimensions. The length is 9 inches, width is 2 inches, and height is 1 1/2 inches. Find the total cost of silver coating for the entire box.

Problem 3 :

Cherise is setting up her tent. Her tent is in the shape of a trapezoidal prism shown below. How many cubic feet of space are in her tent ?

Problem 4 :

Allie has two aquariums connected by a small square prism. Find the volume of the double aquarium.

Solutions

Problem 1 :

Solution :

To know that total cost of painting, first we have to know the Surface area of the jewelry box.

Find surface area of the box.

Step 1 :

Identify a base, and find its area and perimeter.

Any pair of opposite faces can be the bases. For example, we can choose the bottom and top of the box as the bases.

Find base area.

B = l x w

B = 12 x 15

B = 180 square in.

Find perimeter of the base.

P = 2(12) + 2(15)

P = 24 + 30

P = 54 in.

Step 2 :

Identify the height, and find the surface area.

The height h of the prism is 6 inches. Use the formula to find the surface area.

S = Ph + 2B

S = 54(6) + 2(180)

S = 684 square inches

Step 3 :

Total cost = Area x Cost per square in.

Total cost = 684 x $0.50

Total cost = $342

So, Erin has to spend $342 to paint the jewelry box.

Problem 2 :

Solution :

To know that total cost of silver coating, first we have to know the Surface area of the metal box.

Find surface area of the box.

Step 1 :

Identify a base, and find its area and perimeter.

Any pair of opposite faces can be the bases. For example, we can choose the bottom and top of the box as the bases.

Find base area.

B = l x w

B = 9 x 2

B = 18 square in.

Find perimeter of the base.

P = 2(9) + 2(2)

P = 18 + 4

P = 22 in.

Step 2 :

Identify the height, and find the surface area.

The height h of the prism is 1 1/2 inches. Use the formula to find the surface area.

S = Ph + 2B

S = 22(1 1/2) + 2(18)

S = 22(3/2) + 36

S = 33 + 36

S = 69 square inches

Step 3 :

Total cost = Area x Cost per square in.

Total cost = 69 x $1.50

Total cost = $103.50

So, the total cost of silver coating for the entire box is $103.50.

Problem 3 :

Cherise is setting up her tent. Her tent is in the shape of a trapezoidal prism shown below. How many cubic feet of space are in her tent ?

Solution :

Step 1 :

To find the number of cubic feet of space in the tent, we have to find the volume of Cherise's tent.

Step 2 :

Volume of Cherise's tent (Trapezoidal prism) is

= base area x height

V = b x h

Step 3 :

Find base area.

Area of trapezoid with bases of lengths b₁ and b₂ and height h.

Base area (b) = (1/2) x (b₁ + b₂)h

Base area (b) = (1/2) x (6 + 4)4

Base area = 20 sq.ft

Step 4 :

Find volume of the prism.

V = b x h

V = 20 x 9

7th Grade Algebra Word Problems

V = 180 cubic.ft

So, the number of cubic feet of space in Cherise's tent is 180.

Problem 4 :

Allie has two aquariums connected by a small square prism. Find the volume of the double aquarium.

Solution :

Step 1 :

Find the volume of each of the larger aquariums.

Volume = Base area x Height

Volume = (4 x 3) x 3

Volume = 12 x 3

Volume = 36 cubic ft.

Step 2 :

Find the volume of the connecting prism.

Volume = Base area x Height

Volume = (2 x 1) x 1

Volume = 2 x 1

Volume = 2 cubic ft.

Step 3 :

Add the volumes of the three parts of the aquarium.

V = 36 + 36 + 2

V = 74 cubic ft.

The volume of the aquarium is 74 cubic ft.

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